Q: When 4 dice are rolled you get atleat 2 on the dice?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

1/12

It is 5 over 6.

There are 42 or 16 outcomes for rolling 2 described dice. There are 2 ways to obtain a 7: 3,4 & 4,3. So, if two tetrahedral dice are rolled the probability the sum is 7 is 2/16 or 1/8 or 0.125.

6 ways: 1 and 4, 4 and 1, 2 and 3, 3 and 2, 5 and 0, 0 and 5 A five can be rolled with either dice being a 2,3,4,1 and the other dice being the correlating number that adds to five ie. 4-1, 1-4. 3-2. 2-3. There is no 0 on a die.

1 in 9. Since there are 36 (6x6) possible combinations, and 4 of them (1+4, 4+1, 2+3, 3+2) will produce a sum of 5, the probability is 4 in 36, or 1 in 9.

Related questions

When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.

1/12

The are 36 permutations of two dice. Of these, 6 permutations have the two dice with the same number, specifically 1+1, 2+2, 3+3, 4+4, 5+5, and 6+6. The probability, then, that two dice rolled will not have the same number is 30 in 36, or 5 in 6, or about 0.8333.

It is 5 over 6.

The two dice sum of 4: 1,3 2,2 3,1 = 3 in 36 = 1 in 12

1/3 or 4/12

There are 42 or 16 outcomes for rolling 2 described dice. There are 2 ways to obtain a 7: 3,4 & 4,3. So, if two tetrahedral dice are rolled the probability the sum is 7 is 2/16 or 1/8 or 0.125.

6 ways: 1 and 4, 4 and 1, 2 and 3, 3 and 2, 5 and 0, 0 and 5 A five can be rolled with either dice being a 2,3,4,1 and the other dice being the correlating number that adds to five ie. 4-1, 1-4. 3-2. 2-3. There is no 0 on a die.

1 in 9. Since there are 36 (6x6) possible combinations, and 4 of them (1+4, 4+1, 2+3, 3+2) will produce a sum of 5, the probability is 4 in 36, or 1 in 9.

If the die is fair, then 1/6.

There are 21 possible combinations of 2 dice. The total with the most possible combinations is 7, which has three. (6+1,5+2,4+3) This is not right. By this logic 6 and 8 have equal chances of being rolled as I can roll a six through the numbers, 5-1, 4-2, 3-3. When counting the probability of a number to be rolled you have to assume the dice do not care the order in which they are rolled. That is to say, a roll of 5-2, and 2-5 are NOT the same. It is for this reason we find that 7 truly has many more ways a being rolled. 2-5, 5-2, 6-1, 1-6, 3-4, 4-3. While both 6 and 8 have less because one of their dice rolls cannot be counted twice the double roll. For six this is the 3-3 roll, and for eight its the 4-4 roll. That is why 7 is the most common roll on two dice.

P(1or2)=2/6=1/3 P(4<=x<=6)=2/3 when rolled 15 times (2/3)^15=.0023