1,2,3,4,5,6,7,8,9,10,11,12,13,14, etc.
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
The natural numbers are positive integers (whole numbers) starting from one. So, the first natural number is 1, the second natural number is 2, the third is 3, and so on.
Mean = (sum of the n numbers)/n
Eight hundred and eighty-eight.
You divide by the number of numbers - if you want the mean of three numbers you divide by 3, if you want the mean of a hundred numbers you divide by 100.
Their mean is 3.
If you mean larger by "the set of whole numbers strictly contains the set of natural numbers", then yes, but if you mean "the set of whole numbers has a larger cardinality (size) than the set of natural numbers", then no, they have the same size.
That depends what the numbers are.
It means 5 hundred, twenty-six.
Well, write it out, a hundred million is 100,000,000. That is 9 digits, if that's what you mean.
"Natural Numbers" can mean either "Counting Numbers" {1, 2, 3, ...}, or "Whole Numbers" {0, 1, 2, 3, ...}, depending on the subject.