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Program to calculate the sum of first ten natural numbers?
Algorithm to find the sum of first n natural numbers:1. Read n.2. Initialize N=1.3. Initialize sum S=0.4. Calculate S=S+N.5. Calculate N=N+1.6. If N>n, then goto step 7 else goto step 4.7. Write the sum S.8. Stop.
How many prime numbers are there upto 10 20 30 40 50 and so on what will you notice?
Well, you can look it up yourself in a table of prime numbers. But the general tendency is that, the higher you go, the less prime numbers you'll find in each interval. The long-term tendency is that among the first "n" numbers, you'll find n / ln(n) prime numbers, where ln(n) is the natural logarithm. This formula is not terribly accurate for small numbers, but it gets better and better as "n" gets larger.
Identify the difference between natural number and real number?
The set of natural numbers or counting numbers N is a subset of the set of real numbers R. N = {1, 2, 3, ...) R = {..., -2, -1, -0.5, 0, 1, √2, 2, 3, π, ...}
What is the algorithm and flowchart to find Sum of natural numbers from 1 to10?
The general equation to find the sum of the numbers 1 to n is: (n*(n+1))/2So, for n=10, you have:(10*(10+1))/2(10*11)/2110/255
The sum of two consecutive odd numbers is the square of the product of the first and fourth prime numbers what are the two odd numbers?
Let n = smallest of the odd numbers, then let n+2 = the larger of the two numbers (Remember, 1 is not a prime number.) n+ n+2 = {(2)(7)}2 2n +2 = 142 2n = 196 -2 2n = 194 n = 97 n + 2 = 99
