Its length and its perpendicular height
Area = length*height
Area of a parallelogram = length*perpendicular height
They need not be. A bigger triangle can have the same area as a small parallelogram.They need not be. A bigger triangle can have the same area as a small parallelogram.They need not be. A bigger triangle can have the same area as a small parallelogram.They need not be. A bigger triangle can have the same area as a small parallelogram.
You do not need to find. If it is a parallelogram, it must be 180 degrees.
To find area you need base and height of a parallelogram. A = BH Not all the side lengths given would be base or height. Side lengths are perfect to find perimeter but don't rely on the side lengths for area.
depends on the 3 numbers. All you really need is base and height. A = bh
You cannot. You need to know, or be able to calculate, its [perpendicular] height and information about the side lengths is not enough to determine that.A parallelogram can be flexed into a rectangle (when its area is maximised) to a long thin shape with area tending to zero.
You would need to know its side lengths and angles and then you can compute height
find the area of the cross section then multiply by the other dimension (length, height, whatever you are calling it) Area of a parallelogram is base x height, area of a kite might need to be broken into triangles then added together.
Well, honey, finding the area of a parallelogram with 3 numbers is like a piece of cake. You just need to multiply the base by the height, and boom, there's your area. No need to break a sweat over it, darling. Just plug in those numbers and get your answer faster than you can say "math is fun."
Triangles you use : (base x perpendicular height) divided by 2. Parallelogram: you need to find the area of one of the side triangles, then double it (because there's two of them). Then find the area of the square in the middle, and add this to the area of the two triangles.
Length and Width. Area = Length * Width
You don't know and they need not be. There are lots of rectangles.