A resistive load just describes something like a toaster, electric water heater or space heater, where the load is relatively constant. The description is used to distinguish from something like an electric motor, which uses much more current at startup then drops off significantly after it is running.
AnswerIn a.c. circuits, a resistive load describes a load whose load current is in phase with its supply voltage. Expressed another way, it is a load having unity power factor. Resistive loads are not necessarily constant -for example a tungsten-filament lamp has a low resistance when cold and a high resistance at its operating temperature.
1000 milliamperes = 1 amp. Assuming a resistive load, amps = watts / volts = .125 amps or 125 milliamperes
watts = Current x Volts for a resistive load. If you are talking about residential voltage of 120 VAC the formula is A = 12,000 / 120 or 100 Amps. 100. That current can kill you.
If we assume that the inverter is used in your car on 12 Volts DC and you are creating 120 VAC; and the 2500 watts refers to the AC side of inverter then for a resistive load Amps = Watts / Volts = 2500/120.
I = W/E. Current is equal to Watts divided by Volts. 1500/120 = 13 amps. A #14 is rated at 15 amps. A conductor can only be loaded to 80% for a continuous load so 80% of 15 equals 12 amps. Too small for the 1500 watt load. A #12 conductor is rated at 20 amps times 80% equals 16 amps for a continuous load. To answer your question, no, a #16 conductor will not handle a 1500 watt load.
Watts = volts x amps x power factor Power Factor is 1 for resistive loads and decreases for other loads like motors. Maximum watts would be 12 x 220
1000 milliamperes = 1 amp. Assuming a resistive load, amps = watts / volts = .125 amps or 125 milliamperes
watts = Current x Volts for a resistive load. If you are talking about residential voltage of 120 VAC the formula is A = 12,000 / 120 or 100 Amps. 100. That current can kill you.
If we assume that the inverter is used in your car on 12 Volts DC and you are creating 120 VAC; and the 2500 watts refers to the AC side of inverter then for a resistive load Amps = Watts / Volts = 2500/120.
It all depends on the load. The formula for calculating amps, volts or ohms (resistance of load) is E=IR, where E is the voltage, I is the current and R is the load or circuit resistance. So, if you know the resistance in ohms and the current in amps, you multiply them together to get the voltage of the circuit. Again, it depends on the load, so a 12 volt car battery can deliver 1.5 amps if the load is 8 ohms whereas a 120 volt circuit will deliver 1.5 amps if the load is 80 ohms. This is all simplified and is based on a resistive load. If the load is capacitive or inductive, then phase angles come into play and the math is more complicated using imaginary numbers and J-operators.
The amps it draws depends on how big it is. Typically 2-12 amps. Check for a manufacturer's plate that shows the wattage Most of the load in a rice cooker is a resistive heating element, so the amperage will be quite close to the wattage divided by the voltage (220 here).
I = W/E. Current is equal to Watts divided by Volts. 1500/120 = 13 amps. A #14 is rated at 15 amps. A conductor can only be loaded to 80% for a continuous load so 80% of 15 equals 12 amps. Too small for the 1500 watt load. A #12 conductor is rated at 20 amps times 80% equals 16 amps for a continuous load. To answer your question, no, a #16 conductor will not handle a 1500 watt load.
Watts = volts x amps x power factor Power Factor is 1 for resistive loads and decreases for other loads like motors. Maximum watts would be 12 x 220
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
It is a rating for the capacity of the battery to power a load. A battery rated at 15 amp/hrs has the ability to power a load of 15 amps for 1 hour, or 1 amp for 15 hours, or any combination of the two numbers. Example, 2 amps for 7.5 hours, 3 amps for 5 hours or 5 amps for 3 hours etc.
12-2 (#12-2 conductor) wire doesn't "pull" 20 amps. However, it's ampacity rating is that of 20 amps. #12 copper wire is rated for a total load of 20 amps. So, always use a 20 amp breaker with it.
The total load in watts would be W = A x V. 20 x 120 = 2400 watts. Any wattage higher than this will trip the breaker and shut the circuit off. <<>> The theoretical resistive load is V/I = 120/20 = 6 Ohms. The lower the resistance the higher the current. Usually you don't want to operate above the 80% point so the number would be 120/16 = 7.5 Ohms.
In a 12VDC circuit with a 1K load, there will be 12ma of current. (Ohm's law: Volts = Amps * Ohms, so Amps = Volts / Ohms.)