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Are division and subtraction commutative and associative?
No.Neither are commutative: a - b does not equal b - a, and a/b does not equal b/a.Neither is associative: (a - b) - c does not equal a - (b - c), and (a/b)/c does not equal a/(b/c).Examples of these are:4 - 2 does not equal 2 - 4.1/3 does not equal 3/1.(6 - 5) - 1 does not equal 6 - (5 - 1).(10/2)/2 does not equal 10/(2/2).
What does -a-b equal if a equals -4 and b equals 3?
1 is the answer. -(-4)- 3 = 4-3 = 1 .
Which of the expressions is equal to 28A.5+4×2-3+(6×3)B.4+4-3×2+9-(15÷5)C.7×2-5+(6÷2)+4D.(20+5)÷5+7×2-4?
3475636573626758335263257623587365
3 plus 5 equals 4times b therefore b equals?
3 + 5 = 4*b so 8 = 4*b Divide both sides by 4: 2 = b
How many different hands of poker can you make with 7 cards?
There are 20 unique 5-card hands. Solution: First break apart the player card combinations. You can either use player card 1, player card 2, or both player cards 1 and 2 with the hand. Therefore, you are taking 5 cards, 3 at a time, when playing with both player cards, and 5 cards, 4 at a time, when playing with 1 player card. Mathematically, this can be expressed using the Binomial coefficient 2 x ( 5 choose 4 ) + ( 5 choose 3 ) = Number of possible 5-card hands. 5 choose 4 = 5 : This represents the combinations between 1 player card and 5 table cards, 4 at a time. (http://www.wolframalpha.com/input/?i=5+choose+4) 5 choose 3 = 10 : This represents the combinations between 2 player cards, and 5 table cards, 3 at a time. (http://www.wolframalpha.com/input/?i=5+choose+3) Thus, 2 x ( 5 ) + ( 10 ) = 20 . Further Information: All possible hand combinations are listed below. A and B are the two player cards. 0 through 5 are the five table cards. ----- A 1 2 3 4 A 2 3 4 5 A 3 4 5 1 A 4 5 1 2 A 5 1 2 3 B 1 2 3 4 B 2 3 4 5 B 3 4 5 1 B 4 5 1 2 B 5 1 2 3 A B 2 3 4 A B 3 4 5 A B 1 2 3 A B 4 5 1 A B 5 1 2 A B 4 5 2 A B 4 1 2 A B 5 1 3 A B 5 2 3 A B 1 3 5
If a is equal to b. is not a equal to not b?
No because if a=4 and b=4 then a=b and not a can equal 6 and not b can equal 5 so ~a is not = to ~b
Are division and subtraction commutative and associative?
No.Neither are commutative: a - b does not equal b - a, and a/b does not equal b/a.Neither is associative: (a - b) - c does not equal a - (b - c), and (a/b)/c does not equal a/(b/c).Examples of these are:4 - 2 does not equal 2 - 4.1/3 does not equal 3/1.(6 - 5) - 1 does not equal 6 - (5 - 1).(10/2)/2 does not equal 10/(2/2).
If 1 is equal to 5 2 is equal to 25 3 is equal to 325 4 is equal to 4325 then 5 is equal to?
given 1=52=253=3254=4325now the question is 5=?from basic mathematics we have if a=b then b=atherefore if 1=5 then 5=1.hence the answer is 1
What does -a-b equal if a equals -4 and b equals 3?
1 is the answer. -(-4)- 3 = 4-3 = 1 .
the ratio of A to B is 2:3 and the ratio of B to C is 4:5. what is the ratio of A to C?
This deals with ratios and proportions. ⊱ ────── ✯ ────── ⊰ A : B = 2 : 3 B : C = 4 : 5. Now, to find A : B : C, we need to make the value of B equal in A : B ratio and B : C ratio. Here, Value of B in A : B ratio is 3; and B : C ratio is 4. LCM of 3 and 4 is 12. Therefore, we multiply 4 to the first ratio and 3 to the second ratio. A : B = 2 × 4 : 3 × 4 A : B = 8 : 12 Also, B : C = 4 × 3 : 5 × 3 B : C = 12 : 15 Now, we can combine A : B and B : C. A : B : C = 8 : 12 : 15.
Which of the expressions is equal to 28A.5+4×2-3+(6×3)B.4+4-3×2+9-(15÷5)C.7×2-5+(6÷2)+4D.(20+5)÷5+7×2-4?
3475636573626758335263257623587365
What does Pythagorean triple mean in relation to math?
its when you have a right triangle with lengths that equal 3, 4, and 5. A=3 B=4 C=5 C is your hypotenuse (sorry about spelling there)
Is a to the second power over b to the second power greater than a over b?
Let's reverse the question - Is a over b less than a squared over b squared? Answer - Only when a is less than b example 1: a is less than b a = 2 a squared = 4 b = 3 b squared = 9 2 / 3 = .6666 4 / 9 = .444444 2 / 3 is greater than 4 / 9 example 2: a is equal to b a = 2 a squared = 4 b = 2 b squared = 4 2 / 4 = .5 2 / 4 = .5 2 / 4 is equal to 2 / 4 example 3: a is greater than b a = 3 a squared = 9 b = 2 b squared = 4 3 / 2 = 1.5 9 / 4 = 2.25 3 / 2 is less than 9 / 4 - wjs1632 -
3 plus 5 equals 4times b therefore b equals?
3 + 5 = 4*b so 8 = 4*b Divide both sides by 4: 2 = b
If 8 a's 7 b's and 3 c's equal the same as 3 b's 6 a's and 6 c's and a dozen b's equal 3 and a equals two thirds of c what is c's value?
Given that 8a + 7b + 3c = 3b + 6a + 6c, and a = 2/3c, and if 12b = 3, then b = 1/4 Substituting for a and b, 16/3c + 7/4 + 3c = 3/4 + 12/3c + 6c Making 12 the common denominator, 64/12c + 21/12 + 36/12c = 9/12 + 48/12c + 72/12c Combining like terms, 100/12c + 21/12 = 9/12 + 120/12c Grouping like terms, 12/12 = 20/12c Simplifying fractions, 1 = 5/3c Multiplying both terms by 5/3, c = 3/5 And a = 2/3c = 2/3 x 3/5 = 2/5 Checking the answer using a = 2/5, b =1/4, and c = 3/5, Left side = 8a + 7b + 3c = 16/5 + 7/4 + 9/5 = 25/5 + 7/4 = 5 + 1 3/4 = 6 3/4 Right side = 3b + 6a + 6c = 3/4 + 12/5 + 18/5 = 3/4 + 30/5 = 3/4 + 6 = 6 3/4
If A is less than B and B plus C equals 10 and none of them equal zero then which of the following must be true?
You haven't provided any choices for the "which of the following" part of your question. Such questions are best avoided here. However, assuming a, b and c are all natural numbers, all of the following are true for a<b AND b+c=10: a=1, b=2, c=8 a=1, b=3, c=7 a=1, b=4, c=6 a=1, b=5, c=5 a=1, b=6, c=4 a=1, b=7, c=3 a=1, b=8, c=2 a=1, b=9, c=1 a=2, b=3, c=7 a=2, b=4, c=6 a=2, b=5, c=5 a=2, b=6, c=4 a=2, b=7, c=3 a=2, b=8, c=2 a=2, b=9, c=1 a=3, b=4, c=6 a=3, b=5, c=5 a=3, b=6, c=4 a=3, b=7, c=3 a=3, b=8, c=2 a=3, b=9, c=1 a=4, b=5, c=5 a=4, b=6, c=4 a=4, b=7, c=3 a=4, b=8, c=2 a=4, b=9, c=1 a=5, b=6, c=4 a=5, b=7, c=3 a=5, b=8, c=2 a=5, b=9, c=1 a=6, b=7, c=3 a=6, b=8, c=2 a=6, b=9, c=1 a=7, b=8, c=2 a=7, b=9, c=1 a=8, b=9, c=1
How many different hands of poker can you make with 7 cards?
There are 20 unique 5-card hands. Solution: First break apart the player card combinations. You can either use player card 1, player card 2, or both player cards 1 and 2 with the hand. Therefore, you are taking 5 cards, 3 at a time, when playing with both player cards, and 5 cards, 4 at a time, when playing with 1 player card. Mathematically, this can be expressed using the Binomial coefficient 2 x ( 5 choose 4 ) + ( 5 choose 3 ) = Number of possible 5-card hands. 5 choose 4 = 5 : This represents the combinations between 1 player card and 5 table cards, 4 at a time. (http://www.wolframalpha.com/input/?i=5+choose+4) 5 choose 3 = 10 : This represents the combinations between 2 player cards, and 5 table cards, 3 at a time. (http://www.wolframalpha.com/input/?i=5+choose+3) Thus, 2 x ( 5 ) + ( 10 ) = 20 . Further Information: All possible hand combinations are listed below. A and B are the two player cards. 0 through 5 are the five table cards. ----- A 1 2 3 4 A 2 3 4 5 A 3 4 5 1 A 4 5 1 2 A 5 1 2 3 B 1 2 3 4 B 2 3 4 5 B 3 4 5 1 B 4 5 1 2 B 5 1 2 3 A B 2 3 4 A B 3 4 5 A B 1 2 3 A B 4 5 1 A B 5 1 2 A B 4 5 2 A B 4 1 2 A B 5 1 3 A B 5 2 3 A B 1 3 5
