-13
3b -2 =7 b+4
a = 11 and b = 5.
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
(11, 5)
-13
3b -2 =7 b+4
a = 11 and b = 5.
3b+4 = b+12 3b-b = 12-4 2b = 8 b = 4
A plus b 4 can be assumed that mathematically, a = +4.
(11, 5)
b= 4
Write down both equations (I'll label them (1) and (2)):(1) a = 3b - 4(2) a + b = 16Pass b to the left side of the equation (1):(1) a - 3b = -4(2) a + b = 16Multiply (1) by -1:(1) -a + 3b = 4(2) a + b = 16Add down both equations:-a + 3b + a + b = 4 + 164b = 20b = 5Replace b in (2):a + 5 = 16a = 11
-3b = 96 + b Subtract b from both sides: -4b = 96 Divide both sides by -4: b = -24
Such a triangle cannot exist. a = 4 3b = 4 so that b = 4/3 = 1.33.. so that a+b = 5.33... In any triangle, a+b > c Since that is not the case here, the three sides cannot form a triangle.
If a + b = 6, what is the value of 3a + 3b?
If 3b = 39 thenb = 39/3b = 13.