(3b)5 = 243 b5
The actual numerical value depends on the value of ' b ',
and it changes instantly any time ' b ' changes.
No, it is not.
If ( b ) equals 4, then ( 3b ) can be calculated by substituting 4 for ( b ). Thus, ( 3b = 3 \times 4 = 12 ). Therefore, ( 3b ) is equal to 12.
1 raised to any power is always equal to 1.
If the missing operational signs are pluses, that's 3b^2 + 4b + 1
32
No, it is not.
If ( b ) equals 4, then ( 3b ) can be calculated by substituting 4 for ( b ). Thus, ( 3b = 3 \times 4 = 12 ). Therefore, ( 3b ) is equal to 12.
1 raised to any power is always equal to 1.
If the missing operational signs are pluses, that's 3b^2 + 4b + 1
32
243
The answer is 32
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
(b - 1)(3b - 10)
65 = 7,776
335 = 39135393
105 is 100,000