4(3b+2)
4(3b - 5) < -31 + 12b12b - 20 < -31 + 12b, this is not true because -20 > - 31, so that the solution for the given inequality does not exist.
It is not an equation but an algebraic expression that can be simplified to: 12b-5a
(3b)5 = 243 b5The actual numerical value depends on the value of ' b ',and it changes instantly any time ' b ' changes.
If the missing operational signs are pluses, that's 3b^2 + 4b + 1
-9/4b -10/3b =-67/6 9/4b +10/3b = 67/6 27/12b + 40/12b = 67/6 67/12b =67/6 12b = 6 b = 6/12 b=1/2
4(3b+2)
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
4(3b - 5) < -31 + 12b12b - 20 < -31 + 12b, this is not true because -20 > - 31, so that the solution for the given inequality does not exist.
12b - 5 = 15b + 5 subtract 12b from both sides 12b - 12b - 5 = 15b - 12b + 5 - 5 = 3b + 5 subtract 5 from each side - 5 - 5 = 3b + 5 - 5 - 10 = 3b divide both sides integers by 3 - 10/3 = (3/3)b - 10/3 = b ---------------------check in original equation ( change whole numbers to fractions of common denominations ) 12(-10/3) - 15/3 = 15(-10/3) + 15/3 - 120/3 - 15/3 = - 150/3 + 15/3 - 45 = - 45 checks
The group 3B to 12B elements are known as transition metals. They are characterized by their ability to form complex ions with varying oxidation states and exhibit typical metallic properties such as conductivity, malleability, and ductility.
It is not an equation but an algebraic expression that can be simplified to: 12b-5a
Do you mean...? 12b + 8 4(3b + 2) ============( if you meant b12, then there is no factoring possible )
(3b)5 = 243 b5The actual numerical value depends on the value of ' b ',and it changes instantly any time ' b ' changes.
The group 3b-12b elements are known as the transition metals. They are characterized by their ability to form colorful compounds, exhibit variable oxidation states, and have high melting and boiling points. Many transition metals are used in industrial applications and play important roles in biological systems.
In algebra, when you have the expression "3b + b," you can simplify it by combining like terms. In this case, the like terms are both terms with the variable "b." So, 3b + b is equal to 4b. This is because you are adding the coefficients (3 and 1) together while keeping the variable "b" the same.
If the missing operational signs are pluses, that's 3b^2 + 4b + 1