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Consider the meaning of the sine and cosine functions. They are ratios of the side lengths in a right triangle. Sine is the length of the side opposite the angle, divided by that of the hypotenuse, and cosine is the length of the adjacent side, again, divided by the length of the hypotenuse. Consider then:

sin = o/h

cos = a/h

This means that according to our problem, if x is the angle we're measuring in the triangle:

-(o / h) - (a / h) = 0

∴ -o - a = 0

∴ a = -o

Which tells us that the opposite and adjacent sides on our triangle are of equal length. This means that our triangle is not only a right triangle, but an isosceles triangle as well. That means that our angle (x) must be π/4, or 45°

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13y ago
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Q: What does X equal for the equation negative sin x minus cos x equals 0?
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