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Q: What does ab equals 1a plus 1B plus ab equal to?

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1a + 1b because they are different terms and could not be added together. But 1a × 1b would be 1

1a = 1(52)= 52

I--2a+b=2c+2d II--2a+b=c+2d III--a+2b=3d * Here if we perform (I)-(II), we get, c=0 * Using the c we can prove b=0 using (I)-(III). * Now replace 'b' & 'c' as 0 in (I), then we get a=d. Email me at yash2008gates@gmail.com for any queries. I will be very thankful to receive your queries.

algebra 1a is the first part of algebra 1 and algebra 1b is the second part. :)

CCA classification [1]HRA classification[1]CityA-1A-1 [2]BangaloreA-1A-1[3]ChennaiA-1A-1DelhiA-1A-1[4]HyderabadA-1A-1[3]KolkataA-1A-1MumbaiAAAhmedabadAAPuneAASuratAAKanpurAATiruchirapalliAACoimbatoreAALucknowAANagpurAAJaipurAAVisakhapatnamAAVijayawadaAAWarangalB-1B-1KochiB-1B-1PatnaB-1B-1IndoreB-1B-1BhopalB-1B-1GunturB-1B-1VadodaraB-1B-1LudhianaB-1B-1AgraB-1B-1NashikB-1B-1KakinadaB-1B-1RaipurB-1B-2MaduraiB-1B-2VaranasiB-1B-2RajkotB-1B-2RajahmundryB-1B-2JabalpurB-1B-2JamshedpurB-1B-2AllahabadB-1B-2AmritsarB-1CAsansolB-1CDhanbadB-2B-2Hubli-DharwadB-2B-2MysoreB-2B-2MangaloreB-2B-2BhubaneshwarB-2B-2AmravatiB-2B-2AurangabadB-2B-2SrinagarB-2B-2BhilaiB-2B-2NelloreB-2B-2SolapurB-2B-2ThiruvananthapuramB-2B-2RanchiB-2B-2GuwahatiB-2B-2GwaliorB-2B-2ChandigarhB-2B-2JodhpurB-2B-2TiruchirapalliB-2B-2PuducherryB-2B-2JalandharB-2CDehradunB-2CSangliB-2CKozhikodeB-2CBelgaum

No. 1a and 3d are linear, but 2bc is not. ■

It is 1/(ab).

0

It actually is its just that 1b is more in depth of 1a

1a (or just a for short).

3a - 2b = 1

(x + 4) + (x + 5) = 2x + 9

3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2

12 + 1a - 1a + 1 = 1 + 0 + 1 = 2

52

The recommended dose for beta-1a and 1b is 0.03 mg and 0.25 mg, respectively. Initial doses of beta-1b should be far less (i.e., 0.0625 mg), with a gradual increase in dose over six weeks

1a+3b 2a+4b=3a +7b

Here is the java version, C should be similar // merges two Singly linked lists A and B, both sorted in increasing order of integers . // Return a Singly linked list sorted in increasing order // for ex if A = 1->2->3->6 and B = 2->4->7, returns 1->2->2->3->4->6->7 public LinkedList merge(LinkedList A, LinkedList B) { Node 1A = A.head; Node 1B = B.head; Node P1A = NULL; Node 2A = NULL; Node 2B = NULL; while ( 1A != NULL && 1B !=NULL){ 2A = 1A.next; 2B = 1B.next; if (1A.item >= 1B.item) { if (P1A != NULL) { P1A.next = 1B; } else if ( P1A == NULL){ P1A = 1B; } 1B.next = 1A; P1A = 1B; 1B = 2B; } else if ( 1A.item < 1B.item){ if ( 2A != NULL) { P1A = 1A; 1A = 1A.next; } else{ 1A.next = 1B; break; } } } return A; }

1a.) 7433 1b.) -3347 2.) -80 3.) shoelace

Rockwell B-1a The Rockwell B-1A was cancelled because of high costs and was eventually replaced by the B-1B.

English 1a/ 1b

English 1a/1b

A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.

45 is the pass marks for every subject at Anna University

No. Blood group of a person is controlled by 2 alleles, one from each parent. The allele for blood group AB is A and B, while that for group O is O and O. In this case, the only possible combinations for the offspring are AO or BO. As O is recessive, the blood group of the offspring must be either A or B, definitely not AB. To produce a child of blood group AB, the blood groups of the parents must be: 1. AB x AB (both AB) 2. AO x BO (1A and 1B) 3. AA x BO (1A and 1B) 4. AO x BB (1A and 1B) 5. AA x BB (1A and 1B)