1a + 1b because they are different terms and could not be added together. But 1a × 1b would be 1
1a = 1(52)= 52
I--2a+b=2c+2d II--2a+b=c+2d III--a+2b=3d * Here if we perform (I)-(II), we get, c=0 * Using the c we can prove b=0 using (I)-(III). * Now replace 'b' & 'c' as 0 in (I), then we get a=d. Email me at firstname.lastname@example.org for any queries. I will be very thankful to receive your queries.
algebra 1a is the first part of algebra 1 and algebra 1b is the second part. :)
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No. 1a and 3d are linear, but 2bc is not. ■
It is 1/(ab).
It actually is its just that 1b is more in depth of 1a
1a (or just a for short).
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
(x + 4) + (x + 5) = 2x + 9