1a + 1b because they are different terms and could not be added together. But 1a × 1b would be 1
6b+b+b is the same as 6b+1b+1b you can add the numbers together if the variables are the same. 6b+1b+1b=8b
1a+3b 2a+4b=3a +7b
1a.) 7433 1b.) -3347 2.) -80 3.) shoelace
It is: 7b+4b-1b = 10b when simplified
I--2a+b=2c+2d II--2a+b=c+2d III--a+2b=3d * Here if we perform (I)-(II), we get, c=0 * Using the c we can prove b=0 using (I)-(III). * Now replace 'b' & 'c' as 0 in (I), then we get a=d. Email me at yash2008gates@gmail.com for any queries. I will be very thankful to receive your queries.
ab=1a+1b a is equal to either 0 or two, and b is equal to a
algebra 1a is the first part of algebra 1 and algebra 1b is the second part. :)
It actually is its just that 1b is more in depth of 1a
0
It is 1/(ab).
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
(x + 4) + (x + 5) = 2x + 9
The recommended dose for beta-1a and 1b is 0.03 mg and 0.25 mg, respectively. Initial doses of beta-1b should be far less (i.e., 0.0625 mg), with a gradual increase in dose over six weeks
12 + 1a - 1a + 1 = 1 + 0 + 1 = 2
They are smaller cities, under 1 million in population. Some such cities are Thiruvananthapuram and Mangalore, Nashik, Bhopal, Jalandhar, Amritsar, Dehra Dun, Rudrapur, Raipur, Rishikesh-Haridwar, etc..
45 is the pass marks for every subject at Anna University
Here is the java version, C should be similar // merges two Singly linked lists A and B, both sorted in increasing order of integers . // Return a Singly linked list sorted in increasing order // for ex if A = 1->2->3->6 and B = 2->4->7, returns 1->2->2->3->4->6->7 public LinkedList merge(LinkedList A, LinkedList B) { Node 1A = A.head; Node 1B = B.head; Node P1A = NULL; Node 2A = NULL; Node 2B = NULL; while ( 1A != NULL && 1B !=NULL){ 2A = 1A.next; 2B = 1B.next; if (1A.item >= 1B.item) { if (P1A != NULL) { P1A.next = 1B; } else if ( P1A == NULL){ P1A = 1B; } 1B.next = 1A; P1A = 1B; 1B = 2B; } else if ( 1A.item < 1B.item){ if ( 2A != NULL) { P1A = 1A; 1A = 1A.next; } else{ 1A.next = 1B; break; } } } return A; }