m = n/(n-1)
When, in algebra, two letters are written next to each other as a term, such as m and n becoming mn, it means they are multiplied. So mn is a shorter way of writing "m times n" or "m x n"Therefore, when m = 1 and n = 1, mn = 1 x 1 = 1
Yes.
no
m + n = 10000.05m + 0.06n = 57
It would be the same number either way because its addition.
When, in algebra, two letters are written next to each other as a term, such as m and n becoming mn, it means they are multiplied. So mn is a shorter way of writing "m times n" or "m x n"Therefore, when m = 1 and n = 1, mn = 1 x 1 = 1
m(n + 1)
Yes.
no
mn - 4m - 5n + 20 = (mn - 5n) - (4m - 20) = n(m - 5) - 4(m - 5) = (m -5)(n - 4)
mn - 15 + 3m - 5n Rearranging: mn + 3m - 5n - 15 = m(n + 3) - 5(n + 3) = (m - 5)*(n + 3)
m + n = 10000.05m + 0.06n = 57
(m - 5)(n - 4)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Some possibilities are: mn + mp + 3nq + 3pq = (m+3q)*(n+p) mn - mp - 3nq + 3pq = (m-3q)*(n-p) mn + mp - 3nq - 3pq = (m-3q)*(n+p) mn - mp + 3nq - 3pq = (m+3q)*(n-p) If your question is for something else, please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
87
It would be the same number either way because its addition.
If ( mn = 161 ), then ( m = \frac{161}{n} ). Without knowing the value of ( n ), it is not possible to determine the value of ( mm ).