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mn + mp + 3nq + 3pq = (m+3q)*(n+p)
mn - mp - 3nq + 3pq = (m-3q)*(n-p)
mn + mp - 3nq - 3pq = (m-3q)*(n+p)
mn - mp + 3nq - 3pq = (m+3q)*(n-p)
If your question is for something else, please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
15j2(j + 2)
18 + 8x + x = = 18 + 9x = 9(2 + x) which is the factored form of the expression.
"2x(x - 3)"
(4x + 5)(4x - 5)
it is 6n*(n^3 +/- 4n^2 +/- 3) How that remaining cubic expression can be factored depends on the signs.
15j2(j + 2)
18 + 8x + x = = 18 + 9x = 9(2 + x) which is the factored form of the expression.
w - 9 is in its simplest form.
6•2+6•3
"2x(x - 3)"
It's the general form of a quadratic expression and it can be factored providing its discriminant is not less than zero.
(4x + 5)(4x - 5)
First of all, you don't factor an equation. You factor an expression.Next, here is a linear expression that can be factored: [ 96x + 4 ]. The factored form is: 4(24x + 1).Here is a third degree expression: [ 7x3 - 112x ]. The factored form is: 7x (x + 4) (x - 4).
-3
-119
it is 6n*(n^3 +/- 4n^2 +/- 3) How that remaining cubic expression can be factored depends on the signs.
20x + 4 = 4(5x + 1)