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You don't state what the letters stand for, but if velocity (or more accurately, speed) and time then the gradient (dv/dt where "d" means "difference in") will give the acceleration.
At constant speed the line will be horizontal so the gradient will = 0, i.e, neither acceleration nor deceleration.
The slope of graph of V->t gives the acceleration
if the acceleration is constant, then it is a parabola (a=V*t+(at^2)/2). if it isn't, and you are give it's formula in relation to time, then it is possible to find the distance formula by using higher level mathematics(integrals).
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
ds/dt gives the velocity at that instant. So slope gives the velocity
Given a position vs. time graph, all sorts of analyses can be done. The slope through two points on the graph represents the change in position over the change in time, or the velocity. More precisely, this is equal to dx/dt where x models position and t is time. This is known as the derivative of the function. Moreover, we can take d2x/dt2 (the second derivative) to obtain acceleration, another useful thing to know.
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
If an x-t graph is a position-time graph, velocity is the slope of the line on the graph.
if the segments on the disp vs time graph are straight lines, you merely measure the slope of those lines; the velocity is the slope of the lineso if the disp vs time graph shows a straight line of slope 3 between say t=0 and t=4, then you know the object had a constant speed of 3 units between t=0 and t=4;if the disp vs time graph is curved, then you need to find the slope of the tangent line to the disp vs time curve at each point; the slope of this tangent line is the instantaneous speed at the time, and with several such measurements you can construct your v vs t graph
It is the radial velocity: that is, the speed in the direction towards or away from the origin. The slope will not be affected in any way at all by movement in other directions.
The slope of graph of V->t gives the acceleration
A displacement vs. time graph of a body moving with uniform (constant) velocity will always be a line of which the slope will be the value of velocity. This is true because velocity is the derivative (or slope at any time t) of the displacement graph, and if the slope is always constant, then the displacement will change at a constant rate.
if the acceleration is constant, then it is a parabola (a=V*t+(at^2)/2). if it isn't, and you are give it's formula in relation to time, then it is possible to find the distance formula by using higher level mathematics(integrals).
It depends on what x and t are but, in general, yes.
Acceleration.
acceleration is the slope of the v t graph... so the acceleration is constant and negative. In other words, the object is slowing down at a constant rate.
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
Velocity is the slope of the line on a D-t graph