Thousand.
I suspect it could be " k eq 1" , or "k =1".
k and -k right? -k x -1 =k k+k= 2 k= 1 unless you mean multiply then that would be -k x-1 =k k x k= 2 1.4142 rounded to the nearest ten thousandth
What does it mean tho???
If you mean in the group {1, -1, i, -i, j, -j, k, -k}, the identity element is 1.
reactants are favored over products in the reaction
reactants are favored over products in the reaction
if you mean: 2x^k + 4x^k -1 = x^k +1 6x^k - x^k = 1 + 1 5x^k = 2 x^k = 2/5 cannot be solved further without more info. with 2 variables you must have 2 equations to solve further.
1 apple a day keeps the doctor away
If by "k" you mean a thousand, just divide 1 million by a thousand to find the answer.
1 Kelly's Eye in Bingo (bingo call)
Assuming the elements are integer type... a[k] ^= a[k+1]; a[k+1] ^= a[k]; a[k] ^= a[k+1]; ...but if they are not integer type... temp = a[k]; a[k] = a[k+1]; a[k+1] = temp;
Factor them. k2 = k x k k2 - 1 = (k - 1)(k + 1) k2 - 2k + 1 = (k - 1)(k - 1) Combine the factors, eliminating duplicates. k2(k + 1)(k - 1)(k - 1) = k5 - k4 - k3 + k2, the LCM