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What is the formula for the general term of the arithmetic sequence?
an = a1 + d(n - 1)
How do you find out the nth term?
by the general formula ,a+(n-1)*d * * * * * That assumes that it is an arithmetic sequence. The sequence cound by geometric ( t(n) = a*rn ) or power ( t(n) = n2 ) or something else.
Rule to finding terms in a arithmetic sequence?
The nth term of an arithmetic sequence = a + [(n - 1) X d]
What is the simple formula for the nth term of the arithmetic sequence 7 3 -1 -5 -9?
7 - 4n where n denotes the nth term and n starting with 0
What is the Formula for arithmetic progression?
An arithmetic sequence is usually given by a formula in which the nth term, T(n), is given in terms of the first term, a, and the common difference, d: t(n) = a + d*(n-1) where n= 1, 2, 3, etc An alternative is to define it iteratively. Thus: t1 = a tn = tn-1 + d , where n = 2, 3, 4, etc
What is the formula for the general term of the arithmetic sequence?
an = a1 + d(n - 1)
Can a recursive formula produce an arithmetic or geometric sequence?
arithmetic sequence * * * * * A recursive formula can produce arithmetic, geometric or other sequences. For example, for n = 1, 2, 3, ...: u0 = 2, un = un-1 + 5 is an arithmetic sequence. u0 = 2, un = un-1 * 5 is a geometric sequence. u0 = 0, un = un-1 + n is the sequence of triangular numbers. u0 = 0, un = un-1 + n(n+1)/2 is the sequence of perfect squares. u0 = 1, u1 = 1, un+1 = un-1 + un is the Fibonacci sequence.
What recursive formulas represents the same arithmetic sequence as the explicit formula an 5 n - 12?
-7
Can a sequence of numbers be both geometric and arithmetic?
Yes, it can both arithmetic and geometric.The formula for an arithmetic sequence is: a(n)=a(1)+d(n-1)The formula for a geometric sequence is: a(n)=a(1)*r^(n-1)Now, when d is zero and r is one, a sequence is both geometric and arithmetic. This is because it becomes a(n)=a(1)1 =a(1). Note that a(n) is often written anIt can easily observed that this makes the sequence a constant.Example:a(1)=a(2)=(i) for i= 3,4,5...if a(1)=3 then for a geometric sequence a(n)=3+0(n-1)=3,3,3,3,3,3,3and the geometric sequence a(n)=3r0 =3 also so the sequence is 3,3,3,3...In fact, we could do this for any constant sequence such as 1,1,1,1,1,1,1...or e,e,e,e,e,e,e,e...In general, let k be a constant, the sequence an =a1 (r)1 (n-1)(0) with a1 =kis the constant sequence k, k, k,... and is both geometric and arithmetic.
How do you find out the nth term?
by the general formula ,a+(n-1)*d * * * * * That assumes that it is an arithmetic sequence. The sequence cound by geometric ( t(n) = a*rn ) or power ( t(n) = n2 ) or something else.
How do you find terms in arithmetic sequences?
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
What is the formula to find sum of n odd numbers?
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
Rule to finding terms in a arithmetic sequence?
The nth term of an arithmetic sequence = a + [(n - 1) X d]
What is an nth term in an arithmetic sequence?
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
What is the simple formula for the nth term of the arithmetic sequence 7 3 -1 -5 -9?
7 - 4n where n denotes the nth term and n starting with 0
What is the Formula for arithmetic progression?
An arithmetic sequence is usually given by a formula in which the nth term, T(n), is given in terms of the first term, a, and the common difference, d: t(n) = a + d*(n-1) where n= 1, 2, 3, etc An alternative is to define it iteratively. Thus: t1 = a tn = tn-1 + d , where n = 2, 3, 4, etc
How do you use a arithmetic sequence to find the nth term?
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
