(x2 + any number) + (y2 + any number) = 81
x2 + y2 = 81
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
depends on the equation.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
Equation of circle: (x-2)^2 +(y+9)^2 = 49
The radius of the inner circle is sqrt(9) = 3. The radius of the outer circle is therefore 3*3 = 9. The equation for the outer circle is then x^2 + y^2 = 9^2 = 81. (This is an application of Pythagoras' theorem a^2 + b^2 = c^2 in a right-angled triangle by the way)
x^2+y^2=36
The equation of the circle is: x^2 + y^2 = 81
Standard equation for a circle centred at the origin is x2 + y2 = r2 where r is the radius of the circle. If you increase the size of the circle then the radius must increase, so r2 will be larger. eg a circle of radius 2 has the equation x2 + y2 = 4, if the radius increases to 3 then the equation becomes x2 + y2 = 9
x² + y² = 81.
9
x2 + y2 = 81