The length of a triangle can't be expressed in square units and only its area is expressed in square units
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
The perimeter of a rectangle is equal to twice the length plus twice the width, so P = 2l + 2w P = (2x25) + (2x13) P = 50 + 26 P = 76 centimeters
Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
150cm.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
Area=Length X Width
We can use either meter or centimeter to measure a rectangle. For a large area of rectangle we can also use "feet" or " yards". Using "meter" is a convenient form to measure the length of the rectangle.
15 (it is actually really close to 15 and a half)
The perimeter of a rectangle is equal to twice the length plus twice the width, so P = 2l + 2w P = (2x25) + (2x13) P = 50 + 26 P = 76 centimeters
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
Doesn't describe the problem well enough.
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle