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I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.

Q: If the width is 38 centimeter what is the length of the rectangle?

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Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.

It is: 11.5 Check: 2*(7.5+11.5) = 38

The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38

This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.

I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.

Related questions

Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.

The width is 8 feet

The perimeter is 38.

9 cm

Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.

Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.

It is: 11.5 Check: 2*(7.5+11.5) = 38

P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108

The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38

Perimeter = 11+11+8+8 = 38 inches

This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.

The width is 8 feet