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What formula would you use to solve final velocity if you don't know the acceleration or vice versa?
Wiki User
∙ 13y ago
If the initial velocity was zero then final velocity V = 2*S / t
where S = distance covered
and t = time it took
Acceleration a = 2*S / t2
or
a = (V - V0) / t
where (V - V0) is change in velocity.
Wiki User
∙ 13y ago
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How do I rearrange the acceleration formula to solve it for initial velocity?
Where a = (v-u)/t a is acceleration, v is final velocity u is initial velocity t is time so, u=v-at
How do you find acceleration when given time and change of distance and velocity?
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
What is the equation to solve for average acceleration?
AnswerAcceleration = v2 - v1.........................timeAverage Acceleration requires you to average the the initial velocity of your trials and the ending velocity of your trials. You must also find the average for your time trials. Once you achieve these numbers, just plug them into the above formula and you can solve for average acceleration.
An airplane originally at rest on a runway accelerates uniformly at 6 meters per second for 12 seconds During this 12-second interval the airplane travels a distance of approximately?
The formula for distance covered during uniform acceleration isd = 1/2 * (vf + vi) * t (1)Time, t, is given; initial velocity, vi, is 0; but final velocity, vf, is unknown and must be computed from given information. Knowing the rate of acceleration, initial velocity and time, The final velocity may be computed using the formula for average acceleration (actual acceleration under uniform motion) which isa = (vf - vi) / t (2)Rewriting to solve for vf with vi = 0 we havevf = a * tvf = 6m/s2 * 12svf = 72m/sPlugging this value into equation (1) with the other given values we haved = 1/2 * (72m/s + 0 m/s) * 12sd = 432mSo the airplane will travel 432m from rest in 12 seconds under 6m/s uniform acceleration.
How do you find the time from acceleration and distance?
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.
How do I rearrange the acceleration formula to solve it for initial velocity?
Where a = (v-u)/t a is acceleration, v is final velocity u is initial velocity t is time so, u=v-at
How do you find acceleration when given time and change of distance and velocity?
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
What is the formula for aceleration?
The first answer is backward. Acceleration = (final velocity - initial velocity)/total time. For deceleration the formula is the same, the answer will just be negative.Agreed. In physics, there is no "deceleration", only negative acceleration.a = Δv / ΔtThere is no equation for "deceleration" as suggested below.Deceleration=(original velocity-final velocity)/TimeDeceleration In MotionDeceleration = inital speed - final speed / total time taken
How do you find the initial velocity just with the accelaration final velocity and time?
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
What is the equation to solve for average acceleration?
AnswerAcceleration = v2 - v1.........................timeAverage Acceleration requires you to average the the initial velocity of your trials and the ending velocity of your trials. You must also find the average for your time trials. Once you achieve these numbers, just plug them into the above formula and you can solve for average acceleration.
What is the relationship between acceleraion and velocity?
Acceleration increases the velocity. There are two physics formulas that you can use to see more how they interact. The first is a formula for determining your current velocity at a given moment t, knowing your initial velocity and your current acceleration. v = v0 + at (v0 is v-naught. The zero is usually written as a subscript.) You can solve this equation for a to get a formula for acceleration as well. a = (v-v0)/t So, basically, at any given interval t, the acceleration has been added onto the current velocity that many times.
How do you find final velocity without acceleration?
With no acceleration the final velocity is the same as the initial velocity. If the initial velocity is zero, the object is not moving. Unless there is some kind of force influencing the object. Then you have to calculate the acceleration: a=F/m where "F" is the force influencing the object (in Newtons) and "m" is its mass (in kilograms).
What to do if the car change its velocity and the given is the acceleration?
Acceleration equals the change in velocity over a period of time. a= (Vfinal- Vinitial)/t Plug in the acceleration and other information they give you. Then solve.
Calculate the velocity of ball just before it hits the ground when dropped from a height of 6m?
Here are two different methods to solve this kind of problem. 1) Use one of the formulae for constant acceleration. In this case, vf2 = vi2 + 2as, where vf is the final velocity, vi is the initial velocity (zero in this case), a is the acceleration (9.8 meters / second2), and s is the distance. 2) Do an energy calculation, as follows: Calculate the potential energy at a height of 6 meters, with the formula PE = mgh. Since we can assume that the entire potential energy gets converted to kinetic energy just before the ball hits the ground, solve for velocity, in the kinetic energy formula.
When an objects moves in straight line with uniform acceleration which two equations its velocity acceleration and distance?
Suppose v = [final] velocity, a = acceleration and s = distance thenif the initial velocity, u, is known,v^2 - u^2 = 2*a*sand if the elapsed time, t, is known,s = v*t - 0.5*a*t^2The subject of either equation may be changed to solve for the missing variable.
How do you find the initial velocity?
In kinemetics, i learnt that as long as you have three unknowns, you can solve the problem. If you know the distance, d; time, t; and final velocity, vf; you can figure out vi.average velocity = total distance / total timeso d/t = (vi+vf)/22d/t = vi + vf(2d/t) - vf = vihope this helped .good luckRemember that this only works if the acceleration is constant.-Manvith N
An airplane originally at rest on a runway accelerates uniformly at 6 meters per second for 12 seconds During this 12-second interval the airplane travels a distance of approximately?
The formula for distance covered during uniform acceleration isd = 1/2 * (vf + vi) * t (1)Time, t, is given; initial velocity, vi, is 0; but final velocity, vf, is unknown and must be computed from given information. Knowing the rate of acceleration, initial velocity and time, The final velocity may be computed using the formula for average acceleration (actual acceleration under uniform motion) which isa = (vf - vi) / t (2)Rewriting to solve for vf with vi = 0 we havevf = a * tvf = 6m/s2 * 12svf = 72m/sPlugging this value into equation (1) with the other given values we haved = 1/2 * (72m/s + 0 m/s) * 12sd = 432mSo the airplane will travel 432m from rest in 12 seconds under 6m/s uniform acceleration.
