The remainder is 2-p or 0.5p of the original amount.
Roughly a third.
1g (1/2)4 = 1/16 g
Age = no. of half lives x duration of each half life ratio of Parent nuclei : Daughter Nuclei 1 : 15 total of 16 parts, and for every 16 parts one part is a parent nuclei Mt = Mo x (0.5)^n Mt = amount remaining Mo = Initial amount n = number of 1/2 lives Mt = 1/16 (1/2)^n = 1/16 (1/2)^n = (1/2)^4 n=4 Age = 4 x duration of each half life Age = 4 x 300 Age = 1200 Therefore, the age of the specimen is 1200 years.
The answer depends on the total number of students at the school. Since this information has not been disclosed, it is not possible to answer the question.
There is no such word.An integrator is a person or operation that integrates a function.
Approx 1/8 will remain.
12.5%
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
The fraction that remains is 1/8.
Massive nuclei are unable to remain bound aganst the repulsive force of their protons, which all have positive charge. This also occurs with elements #43 (technetium) and #61 (promethium) which because of their particular nuclear geometry are inherently unstable and radioactive, with the only natural isotopes having half-lives of just over 2 years.
1/27 = 1/128 = 0.78125%
1/8 of the original amount remains.
Only 1/32 of the original radioactive material will remain. (½)5 = 1/32
After 6 half lives, the remaining will be (1/2)6 i.e 1/64 th of the initial amount. Hence by percentage it would be 1.5625 %
From a tiny fraction of a second (10-18 seconds or so) to more than 1015 years.
1/2 (50%) of them.
I Led 3 Lives - 1953 Radioactive 3-28 was released on: USA: 1956