Want this question answered?
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
They have the same form for any variables, but the numerical coefficients can be different.
-.12
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
Coefficients don't 'stand' for anything. They are numbers which multiply variables. For instance, in the expression 3 x + 2, three is the coefficient of x.
60b2 you multiply the coefficients then the exopnients 5b1 (next to variables there are invisible exonients) x 12b1 ______ 60b2 (when multiplying like variables you add the exponients)
X2 * 2X= 2X3======multiply coefficients and add exponents ( all variables have a 1 as implied exponent )
Eliminate the variables that have equal coefficients but opposite in sign.x + 2y = 103x - 2y = 14Or you can work to have one of the variables with equal coefficients but opposite in sign such as:3x + 2y = 5x + y = 2 multiply by -2 to both sides3x + 2y = 5-2x - 2y = -4
parameters
yes
We would need to have the list of correlation coefficients to respond to this question.
You are dividing two monomials. Divide the coefficients of the variables, and multiply by the division of the variables. 7b/9b = 7/9 x b/b = 7/9 x 1 = 7/9
Only subtract, if they are pointers to the same type. Example:double coefficients [12], *p= &coefficients[3], *q= &coefficients[4];printf ("q-p=%d\n", (int)(q-p));Note: The result is 1, not sizeof (double)
-85-6x=91+2x
Yes, if they are in common for all the terms.
They have the same form for any variables, but the numerical coefficients can be different.