5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
(-a-7b+5)4ab
0.3333
a^2b^2(4ab) = 8a^3b^3.
(4ab^2 + 3cd)(4ab^2 - 3cd)
Well, isn't that just a happy little math problem we have here? To factorise 4ab - 6ab, we can first factor out the common factor, which is 2ab. So, we have 2ab(2 - 3) or simply 2ab(-1). And just like that, you've simplified the expression beautifully!
4ab - 2a - 7
The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
2a x 3b = 6ab
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
2a*2b = 4ab
Urmm 4ab ?
3a2b is the simplest formImproved Answer:-3a x 2b = 6ab when simplified
5a2 + 6ab=a(5a+6b)
6ab-3b factorize = 3
(-a-7b+5)4ab