To multiply the expressions (4ab) and (6ab), you first multiply the coefficients (the numerical parts) and then multiply the variables. So, (4 \times 6 = 24), and for the variables, (a \times a = a^2) and (b \times b = b^2). Combining these, the product is (24a^2b^2).
To multiply the expressions (6ab) and (3a), you multiply the coefficients and then the variables. The coefficients (6) and (3) multiply to give (18). The variable parts (ab) and (a) combine to give (a^2b). Therefore, the result is (18a^2b).
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
(-a-7b+5)4ab
0.3333
a^2b^2(4ab) = 8a^3b^3.
Well, isn't that just a happy little math problem we have here? To factorise 4ab - 6ab, we can first factor out the common factor, which is 2ab. So, we have 2ab(2 - 3) or simply 2ab(-1). And just like that, you've simplified the expression beautifully!
4ab - 2a - 7
The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
To multiply the expressions (6ab) and (3a), you multiply the coefficients and then the variables. The coefficients (6) and (3) multiply to give (18). The variable parts (ab) and (a) combine to give (a^2b). Therefore, the result is (18a^2b).
2a x 3b = 6ab
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
3a2b is the simplest formImproved Answer:-3a x 2b = 6ab when simplified
Urmm 4ab ?
8a2b
(-a-7b+5)4ab
5a2 + 6ab=a(5a+6b)