By length u mean???? diagonal or height.... it doesnt have length
If you meant all the lengths of the sides- the area would be 4A (the area (A) times by four).
Doubling the base of a triangle while keeping the height constant will double the area of the triangle. The area of a triangle is directly proportional to its base length, so increasing the base length by a factor of 2 will result in the area being multiplied by 2 as well.
the area also doubles
It is double the length of the base, in square units.
To double the area of a square, you must multiply the length of the sides by the square root of 2, √2, which is about 1.414.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
Doubling the base of a triangle while keeping the height constant will double the area of the triangle. The area of a triangle is directly proportional to its base length, so increasing the base length by a factor of 2 will result in the area being multiplied by 2 as well.
the perimeter will double. but the area should doubled to four
the area also doubles
It is double the length of the base, in square units.
To double the area of a square, you must multiply the length of the sides by the square root of 2, √2, which is about 1.414.
Doubling those two dimensions would quadruple the area. So new area = 4*34 cm2 = 136 cm2
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
it would quadruple (become 4 times as big)
If the given length is the measure length of the base of the triangle, then the area of the triangle is: A = (bh)/2 = (10 x 20)/2 = 100.
The area is approximately 71.2 units2
To get the area of a triangle you multiply length by width and divide by two.
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2