An irregular octagon.
t - 8 = 15 To solve for t, we want to get t by itself on one side of the equal sign. So if we are subtracting 8 from t, we need to add 8 to get rid of it, but what we do on one side of equal sign, we need to do to the other side. So t - 8 + 8 = 15 + 8 So t = 15 + 8 So t = 23
No.A regular polygon has equal side lengths and equal angles.
depending if its octagon regular, or irregular (sides arent equal angles arent equal
- x + 8 = 14Subtract 8 from each side:- x = 6Multiply each side by -1 :x = - 6
The third side would be either 5 or 8,as an isosceles triangle has 2 equal sides.
16
If a square has a side length of 4 centimetres, then its area is equal to 4 x 4 = 16cm2 (16 square centimetres).If a square has a side length of 8 centimetres, then its area is equal to 8 x 8 = 64cm2 (64 square centimetres).Therefore, by doubling the side length of a square, the squares area quadruples.
a square has 4 equal side so one side = 32/4 = 8 8 squared = 64cm
Only a regular octagon will have 8 equal sides.
A square has 4 equal sides, so if one side is 8 inches long, your equation would be: 8 X 4 = ? (Once again, you do the math).
If the hypotenuse is equal to 7 and one side is equal to 4, the third side is: 5.745
32 centimeters (a square has four equal sides meaning you can add 8+8+8+8 or multiply 8*4 to get 32