The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
8*length of side.
To find the length of each side of a regular octagon with a perimeter of 56, we divide the perimeter by the number of sides. Since an octagon has 8 sides, we divide 56 by 8 to get 7. Therefore, each side of the regular octagon is 7 units long.
I counted 8. From side-to-side and from point-to-point.
If the octagon is regular, then one side is 39 and there is 8 side, it will be 39*8The answer is 312 cm squaredIf it isn't a regular octagon, then there is no solution
8
"Regular" = all sides are the same length"Octagon" = it has 8 sidesEach side = 25 cmPerimeter = 8 x 25 cm = 200 cm
A regular octagon is a polygon with 8 sides of equal length. To find the area of a regular octagon with a side length of 24 cm, we can use the following formula: Area = (8 × side^2) / (4 × tan(π/8)) where side = 24 cm Plugging in the value, we get: Area = (8 × 24^2) / (4 × tan(π/8)) Area ≈ 736.44 cm^2 So, the area of the regular octagon is approximately 736.44 square centimeters.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
The perimeter would be 64 - since 8 x 8 = 64 !
Each side is 8 inches.
64 cm