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If the point is x=a, y=b, the line is (y-b)=slope times (x-a).

Or, slope=(y-b)/(x-a)

So (y+1/2)=1/2 (x-1/3)

Another answer:-

Point: (1/3, -1/2)

Slope: 1/2

Equation: y - -1/2 = 1/2(x -1/3) => y = 1/2x -2/3

In its general form: 3x -6y -4 = 0

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Q: What in its general form is the straight line equation passing through the point of one third and minus one half with a slope of one half?
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