For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
Y
The equation in slope-intercept form would be y=-2x
What is the equation of the vertical line passing through (-5,-2)
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
The parallel equation will have the same slope but with a different y intercept
3x-4y+1 = 0 Remember that because they are parallel the slope or gradient remains the same but the y intercept value changes.
If you mean: y = 6x-4 then the parallel equation is y = 6x+10
The equation in slope-intercept form would be y=-2x
what
If you mean: y = -x-3 passing through point of (-1, 3) Then the equation of the parallel line is: y =-x+2
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
If you mean: (9, -12) then the equation is y = -12 which is a straight line parallel to the x axis passing through (0, -12)
solve the equation for y to get the slope.y=-2x-1/2substitute (3,3) into the equation/3=2(3)+band solve for b.-3=+by=2x-3 is the equation with the same slope(parallel) and goes through (3,3)
What is the equation of the vertical line passing through (-5,-2)
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
30
The parallel equation will have the same slope but with a different y intercept