-1 -2 -3 -4 -5 -6 and -7 are all greater than -8
Some sources say that the answer is no because a negative integer is less than zero and a positive integer is greater that zero. This answer is partially incorrect because if a negative integer is in an absolute value problem, it can potentially be greater that a positive integer. Example: |-11| > 7 because |-11|=11 because it is in an absolute value problem. Simplified, the problem is 11 > 7 So yes, in some cases a negative integer is greater that a positive integer.
It's not always. 7 + (-3) = 4
In order of greatness they are: -1 -3 -5 and -7
The sum will retain the sign of whichever integer has the higher absolute value. Since 7 is greater than 4, -7 + 4 = -3 7 + -4 = 3
It can be greater than, equal or less than the original integer. There are three possible values for the second integer: It is positive, in which case the result will be less than the original integer, eg 5 - 2 = 3 and 3 < 5;It is zero, in which case the result will be the same as the original integer, eg 5 - 0 = 5 and 5 = 5;It is negative, in which case the result will be greater than the original integer, eg 5 - -2 = 7 and 7 > 5.
3 is the greater number.... -4 is negative - and is 7 less than 3.
yes each and every number is an integer
Yes, technically, since -7 x -4 = 28. We do not generally list negative factors for positive numbers. We do list negative factors for negative numbers.