9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2
Slope-intercept form is y = mx + b5x + 9y = -36Subtract 5x from each side:9y = -5x - 36Divide everything by 9:y = -5/9x - 4
y = (a + 12)(x + 3) (line 1)y = 4ax (line 2)Since the equation of the second line is in a slope-intercept form, write the equation of the first line in the slope-intercept form, y = mx + b, where m is the slope of the line.y = (a + 12)(x + 3)y = a(x + 3) + 12(x + 3)y = ax + 3a + 12x + 36y = ax + 12x + 3a + 36y = (a + 12)x + 3a + 36, where the slope is a + 12y = 4ax, where slope is 4aSince the lines are parallel they must have the same slope. So that,a + 12 = 4a3a = 12a = 4Thus, when a = 4, the parallel lines have a slope of 16.
this is not a valid equation. I assume you mean: 2X+8Y=36 in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2 or 2X+4Y+2=36 in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
1/2x -2/3y = -6 Multiply all terms by 6 to eradicate the fractions: 3x -4y = -36 -4y = -3x -36 Divide all terms by -4: y = 0.75x+9 in slope intercept form
6x - 3y = 36 x intercept: If y = 0, then 6x=36 so x=6 y intercept: If x = 0, then -3y=36 so y = -12
17/12
1/3 because 12/12 =1 and 36/12=3
1/12
15/36 = 5/12
12/36 in its simplest form is 1/3.