this is not a valid equation. I assume you mean:
2X+8Y=36
in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2
or
2X+4Y+2=36
in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2
4y2 + 25y + 6
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
hyperbola
4y2
(2y-11)^2
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
4y2 + 25y + 6
No, it equals 4y2
hyperbola
(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)
4y2
(2y-11)^2
(4y + 1)(y + 6)
2(2)2 + 3(2)(- 4) - 4(- 4)2 8 - 24 - 64 = - 80 ======
4(y + 2)(y + 2)
(y - 5)(4y - 5)
4(y + 2)(y + 2)