It is a graph that looks something like this
X 1 2 3 4 5 6 7 8 9 10
Y 5 10 15 20 25 30 35 40 45 50
And the equation would be Y=5X..... Because of X, Y will result. Generally the first three equations are given and if X is 1 and Y is 4, then X is 2 and Y is 5, then X is 3 and Y is 6, the equation would be Y=X+3.
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
As it appears, there is no equation but an algebraic term.
4y^3 + 48y - 28y^2 = 4y(y - 3)(y - 4)
The three terms are: -3xy2, 2xy and -4y3
It is: 8y8
It is 6.
48
To evaluate the expression (3xy + 4y^3) when (y = 2) and (x = 5), substitute the values into the expression. This gives: [ 3(5)(2) + 4(2^3) = 30 + 4(8) = 30 + 32 = 62. ] Thus, the value of the expression is 62.
4y3(4+5y)Improved Answer:-16y3/20y4 = 4/5y
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