It is 6.
The three terms are: -3xy2, 2xy and -4y3
48
4y^3 + 48y - 28y^2 = 4y(y - 3)(y - 4)
It is: 8y8
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
As it appears, there is no equation but an algebraic term.
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4y3(4+5y)Improved Answer:-16y3/20y4 = 4/5y
To evaluate the expression (3xy + 4y^3) when (y = 2) and (x = 5), substitute the values into the expression. This gives: [ 3(5)(2) + 4(2^3) = 30 + 4(8) = 30 + 32 = 62. ] Thus, the value of the expression is 62.
The LCM will contain all factors including variables. Look at coefficients and find their LCM. Then IF several terms have a common factor with a differnt exponent, use that variable with the largest exponent. If a variable appears in only one term, it will still be part of the LCM with its exponent. EX Find LCM for 14s3 and 6 ---- ANSWER --- 42s3 Ex Find Lcm for 3x2y , 4y3, and 7x --- The LCM is 84x2y3 biggest exponents even if not in all terms.