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If Arnold has a 1.70 in dimes and quarters. He has 3 more dimes then quarters. How many of each coin does he have?
10D + 25Q = 170 and D = Q + 3Substitute: 10(Q + 3) + 25Q = 170ie 10Q + 30 + 25Q = 170ie 35Q = 140so Q = 4, making D = 7
A collection of 30 coins worth 5.50 consists of nickels dimes and quarters there are twice as many dimes as nickeles how many quarters are there?
Let the number of nickels, dimes and quarters be n, d, q respectively. Then n +d + q = 30 5n + 10d + 25q = 550 But d = 2n, so: n + 2n + q = 30 => 3n + q = 30 5n + 10(2n) + 25q = 550 => 25n + 25q = 550 => n + q = 22 Which gives two simultaneous equations to solve, resulting in: n = 4, q = 18 So there are 18 quarters (plus 4 nickels and 8 dimes).
If you have twice as many nickels as quarters how many quarters are there if you have 4.90?
5n + 25q = 490; n = 2q so: 10q + 25q = 490 ie 35q = 490 so q = 14 and n must be 28. 14 x 25c = $3.50, 28 x 5c = $1.40, total $4.90. ...and there you have it!
You have 1000 coins to make 199.90 how many dimes and quarters?
This is a system of equations. Let d= number of dimes. q= number of quarters. d+q=1000 -> 10d + 10q = 10000 .10d+.25q=199.90-> -10d+(-25q)=-19990 Multiply each equation to get one of the variables to drop out. Add the equations. (-15q)=(-9990) q=666 1000-666=334 There are 666 quarters and 334 dimes.
The machine only takes dimes and quarters and it has 52 coins worth 8.95 how many of each domination of coins are contained?
Given: 10d + 25q = 895 cents d + q = 52 coins Multiply everything in the second equasion by 10 (to get rid of the dimes). 10d + 10q = 520 Subtract this 3rd equation from the 1st equation: 10d + 25q = 895 10d + 10d = 520 Giving you: 15q = 375 Divide both sides by 15 and you get q = 25 This means you have 25 quarters ($6.25) and 27 dimes ($2.70) CHECK: 25 quarters + 27 dimes = 52 coins (CORRECT) $6.25 + $2.70 = $8.95 (CORRECT)
Leo has 4.80 in dimes and quarters He has 6 more dimes than quarters How many quarters does he have?
Work in cents... 10D + 25Q = 480 and D = Q + 6Substitute: 10(Q + 6) + 25Q = 48010Q + 60 + 25Q = 48035Q = 420Q = 12, making D = 18
If Arnold has a 1.70 in dimes and quarters. He has 3 more dimes then quarters. How many of each coin does he have?
10D + 25Q = 170 and D = Q + 3Substitute: 10(Q + 3) + 25Q = 170ie 10Q + 30 + 25Q = 170ie 35Q = 140so Q = 4, making D = 7
Marcy has a total of 100 dimes and quarters if the total value of the coins is 14.05 how many quarters does she have?
Work in cents...10D + 25Q = 1405 and D = 100 - QSubstitute: 10(100 - Q) + 25Q = 1405ie 1000 - 10Q + 25Q = 1405ie 15Q = 405so Q = 27, making D = 73
Leah has 4.05 in quarters and dimes If she has 5 more quarters than dimes how many does she have?
Work in cents...10D + 25Q = 405 and D = Q - 5Substitute: 10(Q - 5) + 25Q = 405ie 10Q - 50 + 25Q = 405ie 35Q = 455so Q = 13, making D = 8
6.75 in quarters and dimes he has 8 more dimes than quarters how many dimes and quarters does Ben have?
Work in cents...10D + 25Q = 675 and D = Q + 8Substitute: 10(Q + 8) + 25Q = 675ie 10Q + 80 + 25Q = 675ie 35Q = 595so Q = 17, making D = 25
What is the mos 25Q?
Multi-Channel Transmission System Operator Maintainer
A jar contains 55 quarters and dimes The total value of the coins is 8.50 How many quarters and dimes are there all together?
Work in cents...10D + 25Q = 850 and D = 55 - QSubstitute: 10(55 - Q) + 25Q = 850ie 550 - 10Q + 25Q = 850ie 15Q = 300so Q = 20, making D = 35
You have 9.45 in quarters and dimes in your pocket The number of dimes is 18 less than twice the number of quarters How many of each do you have in your pocket?
d = 2q - 18; 10d + 25q = 945 10(2q - 18) + 25q = 945 20q - 180 + 25q = 945 45q = 1125 q = 25 You have 32 dimes ($3.20) and 25 quarters ($6.25)
Explain with workings What is the smallest positive integer q such that 25q is a perfect cube?
5
25q on tt?
25 questions on this test. it is the 25th question on the test. funny huh?
How many quarts of applesauce in a bushel of apples?
16 quarts
A collection of 30 coins worth 5.50 consists of nickels dimes and quarters there are twice as many dimes as nickeles how many quarters are there?
Let the number of nickels, dimes and quarters be n, d, q respectively. Then n +d + q = 30 5n + 10d + 25q = 550 But d = 2n, so: n + 2n + q = 30 => 3n + q = 30 5n + 10(2n) + 25q = 550 => 25n + 25q = 550 => n + q = 22 Which gives two simultaneous equations to solve, resulting in: n = 4, q = 18 So there are 18 quarters (plus 4 nickels and 8 dimes).
