x-2(x)+4/x^2 -4=x-2x+4/x^2 -4=-x-4+4/x^2
-2
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4
x^2/x +2=4/x +2 (x^2/x)-(4/x)=0 (x^2-4)/x=0 x^2-4=0 (x+2)(x-2)=0 x=±2
(x^2-4) (x^2+6x+8) __________ x _________ which is (x^2+2x-8) (x^2+4x+4) (x+2)(x-2) (x^2+4x+2x+8) ___________ x _____________ which is (x^2+4x-2x-8) (x^2+2x+2x+4) (x+2)(x-2) x(x+4)+2(x+4) ___________ x ____________ which is x(x+4)-2(x+4) x(x+2)+2(x+2) (x+2)(x-2) (x+2)(x+4) ________ x _________ which is 1 as all the terms in the num & den cancel (x-2)(x+4) (x+2)(x+2)
x/4 - 4 = -2 Therefore, x/4 = -2 + 4 = 2 Therefore, x = 2 x 4 x = 8
x^(2-x-6)/x^(2-4) x^(-4-x)/x^-2(x^-2)*(x^(-2-6))= x^(-2-x)
-4
You find numbers that divide evenly into 64, such as for example, 1, 2, 4, 8, 16, 32, and 64. Then sharpen your pencil and start writing. 1 x 64 = 64 2 x 32 = 64 4 x 16 = 64 8 x 8 = 64 2 x 2 x 16 = 64 2 x 4 x 8 = 64 4 x 4 x 4 = 64 2 x 2 x 2 x 8 = 64 2 x 2 x 4 x 4 = 64 2 x 2 x 2 x 2 x 4 = 64 2 x 2 x 2 x 2 x 2 x 2 = 64
If that's -8x, the answer is (x - 4)(x - 4) or (x - 4)2 If that's +8x, the answer is (x + 4)(x + 4) or (x + 4)2
10 = 2 x 5, 24 = 2 x 3 x 4, 32 = 2 x 4 x 4, accordingly, LCM = 2 x 5 x 3 x 4 x 4 = 480
x/(x + 4) = 4/(x + 4) + 2 (x - 4)/(x + 4) = 2 x - 4 = 2x + 8 -x = 12 x = -12