75 x 3 = 225
GCF(75x3, y2, 100xy) = 1 However, GCF(75x3y2, 100xy) = 25xy
75x(3y)2 and 100xy both have factors of * * * * * It would appear that the question is looking for the GCF of 75x3, y2 and 100xy. If that is the case, the answer is 1.
75x3, /2, +1, x3...10 x3=30 /2=15 +1=16 x3=48 /2=24 +1=25 x3=75
A multiplicative inverse of 5 mod7 would be a number n ( not a unique one) such that 5n=1Let's look at the possible numbers5x1=5mode 75x2=10=3 mod 75x3=15=1 mod 7 THAT WILL DO IT3 is the multiplicative inverse of 5 mod 7.What about the others? 5x4=20, that is -1 mod 7 or 65x5=25 which is 4 mod 75x6=30 which is -5 or 2 mod 7How did we know it existed? Because 7 is a prime. For every prime number p and positive integer n, there exists a finite field with pn elements. This is an important theorem in abstract algebra. Since it is a field, it must have a multiplicative inverse. So the numbers mod 7 make up a field and hence have a multiplicative inverse.
Considering that 1 person from the 4 person crew is late by 1 hour, the work is done for 1 hr by a 3 person crew. the 3 person crew completes 100% of the job in 4 hrs, hence, in 1 hr it completes 25 % of the job.Now when 75% of the job is unfinished, the 4th member joins, so now it is a 4 person crew to do 75% of the job. If they can complete 100% job in 3hrs, they would complete the 75% job in 2.25 hrs (75x3/100).Hence total time rquired for completion of the job = 2.25 + 1= 3.25 hrs ie 3 hrs 15 minutes.