(-105) + 113 = 8
113 is prime. 117 and 105 are composite.
They are: 1*113 = 113
35 70 105 140 etc 3 x 35 = 105 with 8 remaining
113 is a prime number. Its only factors are 1 and 113.
If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)
It is the square root of 11.3
They are one and itself because 113 is a prime number
Itself and one because 113 is a prime number
113 is a prime number. It is divisible only by 1 and itself.
Only itself and one because 113 is a prime number
45°C = 113°F45°C multiplied by 1.8 +32 = 113°F