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Q: What is 1.05 multiplied by itself 113 times?

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(-105) + 113 = 8

They are: 1*113 = 113

113 is prime. 117 and 105 are composite.

35 70 105 140 etc 3 x 35 = 105 with 8 remaining

113 is a prime number. Its only factors are 1 and 113.

If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)

It is the square root of 11.3

Itself and one because 113 is a prime number

One and itself.

113 is a prime number. It is divisible only by 1 and itself.

Itself and one because 113 is a prime number

They are one and itself because 113 is a prime number

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