(-105) + 113 = 8
113 is prime. 117 and 105 are composite.
They are: 1*113 = 113
113 is a prime number. Its only factors are 1 and 113.
If there is a remainder of 8 when they divide into 113, then they must be factors of 113 - 8 = 105, but not factors of 113, and greater than 8: The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105 The factors of 113 are: 1, 113 Thus the 3 numbers which divide 113 with a remainder of 8 are 15, 21, 35, 105 (oops, there are 4 numbers which satisfy the criteria - I never could count...)
Well, darling, I hate to break it to you, but 113 is a prime number, which means it can only be divided by 1 and itself. So, the answer to your question is simply 1 times 113. Math can be a real buzzkill sometimes, huh?
Oh, dude, let me bust out my calculator for this intense math problem... Okay, so 35 goes into 113 three times with a remainder of 8. So, like, you can fit 35 into 113 three whole times, but there's still a little bit of 113 leftover that 35 couldn't handle. Math, man, it's wild.
It is the square root of 11.3
Itself and one because 113 is a prime number
They are one and itself because 113 is a prime number
113 is a prime number. It is divisible only by 1 and itself.
Only itself and one because 113 is a prime number