Q: What is 10X plus 6Y equals 100 if 6X plus 10Y equals 92?

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10x+10y+100 There is a common 10 in each number. 10(x+y+10)

y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8

10y plus 40 equals 50y.

x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2

x = 6y = 89x + 10y = 9(6) + 10(8) = 54 + 80 = 134

Related questions

10x+10y+100 There is a common 10 in each number. 10(x+y+10)

y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8

y - intercept = 10x - intercept = -10y- intercept: x = 0y = x + 10y = 0 + 10y = 10x - intercept: y = 0y = x + 100 = x + 10x + 10 = 0x = -10

10x-10y = 0

10y plus 40 equals 50y.

If you mean: -10x-10y = -20 then x intercept is at (2, 0) and y intercept at (0, 2)

10y = 9y + 4, so y = 4

Y-8x plus 9y equals 10y-8x.

yes that is correct

10y= 6y+5+3y 10y=6+9y y=6

x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2

Y=-1/2(x)