X=7 y=5
10x+10y+100 There is a common 10 in each number. 10(x+y+10)
y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8
10y plus 40 equals 50y.
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
x = 6y = 89x + 10y = 9(6) + 10(8) = 54 + 80 = 134
10x+10y+100 There is a common 10 in each number. 10(x+y+10)
y + x = 9 10y + 20x = 100 This is a basic linear system of equalities. We can start by rewriting the first equation as: -10y - 10x = -90 by multiplying the equation by -10, from here we can eliminate y and solve for x (-10y - 10x = -90) + (10y + 20x = 100) = (10x = 10) This yields x = 1, and by plugging x into the first equation y = 8
y - intercept = 10x - intercept = -10y- intercept: x = 0y = x + 10y = 0 + 10y = 10x - intercept: y = 0y = x + 100 = x + 10x + 10 = 0x = -10
10x-10y = 0
10y plus 40 equals 50y.
If you mean: -10x-10y = -20 then x intercept is at (2, 0) and y intercept at (0, 2)
10y = 9y + 4, so y = 4
Y-8x plus 9y equals 10y-8x.
yes that is correct
10y= 6y+5+3y 10y=6+9y y=6
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
Y=-1/2(x)