25 squared plus 49 squared is equal to 3,026.
(5r - 4)(5r + 4)
(3y - 5)(y + 5)
(x^2 - 3x + 5)(x^2 + 3x + 5)
If: x^2+y^2 = 12x-10y-12 Then: x^2+y^2-12x+10y = -12 Completing the squares: (x-6)^2+(y+5)^2 -36-25 = -12 So: (x-6)^2+(y+5)^2 = 49 Therefore the centre of the circle is at (6, -5) and its radius is 7
(x-5i)(x+5i)
yes that is correct
25 squared plus 49 squared is equal to 3,026.
(x + 5)(x + 5)
(5r - 4)(5r + 4)
(2x - 5)(2x - 5) or (2x - 5) squared
(3y - 5)(y + 5)
52 + 52 = 25 + 25 = 50
(x^2 - 3x + 5)(x^2 + 3x + 5)
x(x - 25)(x - 25)
If x is equal to 5, then x squared plus 25 is equal to 50.
The answer is 29. Bcause 2 squared is 4 & 5 squared is 25. 25+4=29.