I feel a trick question coming on, but I will bite and say, '40'.
if 9/10 =45, then the full sum is 50 (45/9x10) If you want to find 9/10, then it's (45/10x9) which is 40.5
(45 + n) - 4 That's exactly the same thing as (41 + n).
0.45 is 10% less than 0.5 .
45+3=48 and both the numbers that you are adding are slightly bigger than these. So their sum must be bigger than 48.
45 - 35 = 10 45 + 35 = 80
36 and 45 = 81.
66.66% less than 45 = 33.34% of 45 = 15.003
Was that supposed to say "9/10 of a sum of money is 45"? If so, then the answer is "50". Divide 45 by 9/10, or 0.9. So 45/.9=50
Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Subract 9 with each no mentioned above output is 9,18,27,36,45,54,63,72 See after 4th comma 54 and 45. Reverse 54=45. now 45 is 9 less than 54. So the original no is 54
0.8 is 8/10 or 80/100. 0.45 is 45/100. 80/100 is greater than 45/100.
A list of multiples of 5 that are less than 50: 10, 15, 20, 25, 30, 35, 40, 45