That is a quadratic equation. You can solve it easily if you factor it to 2(2x - 1)(3x - 2) and find what makes each factor 0. The solutions are 1/2 and 2/3; you can see the steps taken to get here using the link under "related links".
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
22 = 4
x = y = 0 ?
That would still be 4. If it were times 0 it would be 0.
-7
1 plus 1 plus 1 plus 1 equals 1 times 4. 1 times 4 equals 4. 4 minus 4 equals 0. 0
22 = 4
x = y = 0 ?
x + 3y = 4 -x + 2y = -4 Simultan eous eq'ns. Eliminate 'x' by adding. 4 Hence 5y = 0 y = 0 When y = 0 Substitute x + 3(0) = 4 x + 0 = 4 x = 4 So the answer as a coordinate pairs is ( x,y) = ( 4,0)
4(x + 1) = 0.
That would still be 4. If it were times 0 it would be 0.
x = 0
x = 0 and y = 4
-7
well it equals 4 any way you put
4+4=8+0=8+1=9+1=10+0=10+1=11 It equals 11. You're welcome.
5n+4=0 5n=-4 n= -4/5