x=4
y=0
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10y = 9y + 4, so y = 4
Subtract first from second gives -4x = 16 so x = -4 and y = -7
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
4x+3y = 6 3y = -4x+6 y = -4/3x+2 in slope intercept form
x-(x-2y)+z=-9 3y-2z=4 2x+y+5z=-5 x-(x-2y)+z=-9 --distribute negative through bracket--> x-x+2y+z=-9 x-x+2y+z=-9 --combine like terms (x)--> 2y+z=-9 2y+z=-9 --isolate z--> z=-9-2y substitute z into second equation: 3y-2(-9-2y)=4 --multiply -2 through bracket--> 3y+18+4y=4 3y+18+4y=4 --subtract 18 from both sides--> 3y+4y=-14 3y+4y=-14 --combine like terms--> 7y=-14 7y=-14 --divide both sides by 7--> y=-2 Substitute value of y into simplified first equation: z=-9-2(-2) --multiply through the bracket--> z=-9+4 z=-9+4 --combine like terms--> z=-5 Substitute values of y and z into third equation: 2x+(-2)+5(-5)=-5 --multiply through brackets--> 2x-2-25=-5 2x-2-25=-5 --combine like terms--> 2x-27=-5 2x-27=-5 --add 27 to both sides--> 2x=22 2x=22 --divide both sides by 2--> x=11 x=11, y=-2, z=-5