135=3s +15
120=3s
40=s
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∙ 12y agomath
s = 15
2h2s + so2 ----------> 3s + 2h2o
decomposition
2Al+3S--->Al2S3
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
2s + s + 12 = 132 3s + 12 = 132 3s = 132 - 12 3s = 120 s = 40
3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)
3s + 1
Through a process of elimination and substitution the solutions are s = 8 and x = 5
2h2s + so2 - 2h20 + 3s
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.