They are simultaneous equations and their solutions are x = 41 and y = -58
The solutions are: x = 4, y = 2 and x = -4, y = -2
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
Without any equality signs the given expressions can't be considered to be simultaneous equations and so therefore no solutions are possible.
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
There are two solutions and they are: x = -1 and y = 3
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
They are two equations in two unknown variables (x and y), which are inconsistent. That is to say, there is no simultaneous solution. An alternative approach is to say that they are the equations of two lines in the Cartesian plane. The lines are parallel and so they do not meet indicating that there is no simultaneous solution.
Simultaneous equations: x/3 -y/4 = 0 and x/2 +3y/10 = 27/5 Multiply all terms in the 1st by 12 and in the 2nd equation by 10 So: 4x -3y = 0 and 5x +3y = 54 Add both equations together: 9x = 54 => x = 6 Solutions by substitution: x = 6 and y = 8
If you mean: x+y = 8 and -x+2y = 7 then they are simultaneous equations whose solutions are x = 3 and y = 5
Only one: (3,-2)
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
It is a simultaneous equation and when solved its solutions are x = 71/26 and y = 50/13
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5
Without any equality signs the given terms can't be considered as simultaneous equations and so therefore no solutions are possible.
Add the two equations together. This will give you a single equation in one variable. Solve this - it should give you two solutions. Then replace the corresponding variable for each of the solutions in any of the original equations.
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.