It simplifies to 5 over 12.
5 over 12
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
150%
(30+360*k) and (150+360*k) degrees where k is any integer.
116 over 360 = 0.3222
5 over 12
First start by reducing 2,670 down to be greater than 0 but less than 360. We can find co-terminal angles to 2,670 by subtracting 360: 2,670-360=2,310 2,310-360=1,950 1,950-360=1,590 1,590-360=1,230 1,230-360=870 870-360=510 510-360=150 So, now the problem is Tan(150). This is equal to the Sin(150)/Cos(150). The Sin(150)=1/2 and Cos(150)=-sqrt(3)/2 So Sin(150)/Cos(150)=[1/2]/[-sqrt(3)/2]=[1/2]*[2/-sqrt(3)]=-1/sqrt(3)=-sqrt(3)/3 So Tan(2,670)=-sqrt(3)/3 ("Negative square root of three over three")
Oh, dude, 150 percent of a 360-degree circle is like adding 50 percent more to it, right? So, 50 percent of 360 is 180, and if you add that to the original 360, you get 540 degrees. So, technically, 150 percent of a 360-degree circle is 540 degrees. Just imagine a circle doing a little extra stretch, you know?
360
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
360
150%
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
(30+360*k) and (150+360*k) degrees where k is any integer.
50
$150-$200
Try eBay.