First start by reducing 2,670 down to be greater than 0 but less than 360.
We can find co-terminal angles to 2,670 by subtracting 360:
2,670-360=2,310
2,310-360=1,950
1,950-360=1,590
1,590-360=1,230
1,230-360=870
870-360=510
510-360=150
So, now the problem is Tan(150).
This is equal to the Sin(150)/Cos(150). The Sin(150)=1/2 and Cos(150)=-sqrt(3)/2
So Sin(150)/Cos(150)=[1/2]/[-sqrt(3)/2]=[1/2]*[2/-sqrt(3)]=-1/sqrt(3)=-sqrt(3)/3
So Tan(2,670)=-sqrt(3)/3 ("Negative square root of three over three")
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There is no value cot 0, because cot 0 is equivalent to 1 / tan 0, which is equivalent to 1 / 0, which is undefined. That said, the limit of cot x as x approaches 0 is infinity.
Yes; a line at 45 degrees.
The exact value is an irrational number, and can't be written on paper with digits.0.34202 is less than 0.000042 percent wrong.Cos(70 deg) is an irrational number and it is impossible to give its exact value.
SQRT(3)/4 - 1/4
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)