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First start by reducing 2,670 down to be greater than 0 but less than 360.
We can find co-terminal angles to 2,670 by subtracting 360:
2,670-360=2,310
2,310-360=1,950
1,950-360=1,590
1,590-360=1,230
1,230-360=870
870-360=510
510-360=150
So, now the problem is Tan(150).
This is equal to the Sin(150)/Cos(150). The Sin(150)=1/2 and Cos(150)=-sqrt(3)/2
So Sin(150)/Cos(150)=[1/2]/[-sqrt(3)/2]=[1/2]*[2/-sqrt(3)]=-1/sqrt(3)=-sqrt(3)/3
So Tan(2,670)=-sqrt(3)/3 ("Negative square root of three over three")
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Yes; a line at 45 degrees.
What is the exact value of cos 70 degrees?
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Using exact values find the numerical value of sin 30 degrees cos 240 degrees plus sin 210 degrees sin 300 degrees?
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What is the exact trigonometric function value of cot 15 degrees?
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
