5 over 12
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
150%
(30+360*k) and (150+360*k) degrees where k is any integer.
116 over 360 = 0.3222
5 over 12
Oh, dude, 150 percent of a 360-degree circle is like adding 50 percent more to it, right? So, 50 percent of 360 is 180, and if you add that to the original 360, you get 540 degrees. So, technically, 150 percent of a 360-degree circle is 540 degrees. Just imagine a circle doing a little extra stretch, you know?
First start by reducing 2,670 down to be greater than 0 but less than 360. We can find co-terminal angles to 2,670 by subtracting 360: 2,670-360=2,310 2,310-360=1,950 1,950-360=1,590 1,590-360=1,230 1,230-360=870 870-360=510 510-360=150 So, now the problem is Tan(150). This is equal to the Sin(150)/Cos(150). The Sin(150)=1/2 and Cos(150)=-sqrt(3)/2 So Sin(150)/Cos(150)=[1/2]/[-sqrt(3)/2]=[1/2]*[2/-sqrt(3)]=-1/sqrt(3)=-sqrt(3)/3 So Tan(2,670)=-sqrt(3)/3 ("Negative square root of three over three")
360
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
150%
360
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
(30+360*k) and (150+360*k) degrees where k is any integer.
50
Well, isn't that just a happy little question! To find the radius when you have the angle and arc length, you can use the formula: radius = (arc length) / (angle in degrees) * (π/180). Just plug in the values you have, and you'll have your radius in no time. Remember, there are no mistakes, just happy little accidents in math!
$150-$200