5 over 12
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
150%
(30+360*k) and (150+360*k) degrees where k is any integer.
116 over 360 = 0.3222
5 over 12
150% of 360 degrees= 150% * 360= 1.5 * 360= 540 degrees
First start by reducing 2,670 down to be greater than 0 but less than 360. We can find co-terminal angles to 2,670 by subtracting 360: 2,670-360=2,310 2,310-360=1,950 1,950-360=1,590 1,590-360=1,230 1,230-360=870 870-360=510 510-360=150 So, now the problem is Tan(150). This is equal to the Sin(150)/Cos(150). The Sin(150)=1/2 and Cos(150)=-sqrt(3)/2 So Sin(150)/Cos(150)=[1/2]/[-sqrt(3)/2]=[1/2]*[2/-sqrt(3)]=-1/sqrt(3)=-sqrt(3)/3 So Tan(2,670)=-sqrt(3)/3 ("Negative square root of three over three")
360
Internal angle = 150° → external angle = 360° - 150° = 30° number of sides = 360 ° ÷ external angle = 360° ÷ 30° = 12 It has 12 sides.
150%
360
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
(30+360*k) and (150+360*k) degrees where k is any integer.
50
150 deg is 150/360 of a complete circle circumference, so the arc length 330cm = 150/360 times 2pi.R This can be solved for R to get R = 330x360/150/(2pi).
$150-$200