17/25 = 68%
20%
It is alleged, but not proven that 2,395 B-17's completed 25 mission tours during World War 2.
21/25 is in its simplest form.
Apply Pythagoras h^2 = l^2 + s^2 h = 25 l = s + 17 Substitute 25^2 = s^2 + ( s + 17)^2 625 = s^2 + s^2 + 34s + 289 Equating to zero 2s^2 + 34s - 336 =0 Divide by '2' s^2 + 17s - 168 =0 Factor ( s + 24)(s - 7) = 0 Hence s = 7 (& s = -24 is unresolved).
25 A quarter is 25/100
If you mean 4/25, that would be 0.16.
over 25's
7/25
In order to find the radius of the inscribed circle we have to find the other side'lenght. We will use the property of the right triangle: c^2=a^2+b^2. In our case a = 8 (half of 16 since in this case the altitude is also a median) and b=15 ( the altitude). Using this formula we find that c^2=289 or c=sqrt(289) or c=17. Now that we know all the sides of the triangle we are going to use the following formula r=sqrt[(s-a)(s-b)(s-c)\s] where "r" is the radius of the inscribed circle and "s" is the semiperimeter of the triangle or s=a+b+c\2=16+17+17\2=50\2=25. Now substituting in the formula r=sqrt[(s-a)(s-b)(s-c)\s] we get r=sqrt[(25-17)(25-17)(25-16)\25]=sqrt[8.8.9\25]=sqrt[576\25]=24\5=4,8 . And so we have found the radius of the inscribed circle: r=4,8
Latitude: 17°51′S Longitude: 25°52′E
17/50
The whole number in simplest form for 25 over 5 is five (5).